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SQL Server, like most of Microsoft's products (Windows, .NET, NTFS, …) uses UTF-16 to store text, in which a character takes up either two or four octets, although as @SQLMenace points out, current versions of SQL Server use compression to reduce that. 500 bytes because each character is 8 1's or 0's which is 1 byte. How many words is 250 characters? 50 words.
2017-01-19 In this case, 11 Bytes could account for less than 11 characters. Also those field types might be treated differently in regard to accented characters or case, for example 'binaryField(ete) = "été"' will not match while 'charField(ete) = "été"' might (again not sure about Oracle). 2014-08-09 This conversion of 500 megabytes to bytes has been calculated by multiplying 500 megabytes by 1,048,576 and the result is 524,288,000 bytes. 500 Megabytes (MB) = 524,288,000 Bytes (B) 1 MB = 1,048,576 B. 1 B = 0.000001 MB 2013-08-27 2016-01-01 Single-byte characters (up to 256 character codes) are used in English and European languages because such languages do not contain very many characters. Japanese, however, has kanji, hiragana and katakana characters in addition to Arabic numerals and the Roman alphabet, so it uses double-byte characters (2 bytes per character; up to 65,536 character codes). In bytes: VARCHAR2 (10 byte).
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Assuming an average for this is 5 To help make data more accessible and simplified, groups of bits are joined into bytes; one byte is comprised of 8 bits. A set of 8 bits was chosen because this provides 256 total possibilities, which is sufficient for specifying letters, numbers, spaces, punctuation and other extended characters.
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4 Mbps to byte/second = 500000 byte/second. 5 Mbps to byte/second = 625000 byte/second. 6 Mbps to byte/second = 750000 byte/second. 7 Mbps to byte/second = 875000 byte/second The difference between the encodings is how many bytes are required to represent any of 1,114,112 Unicode glyphs in memory.
43 LENGTH(char) Length of char in bytes. OTHER
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2013-08-27 · Each letter or character consists of 8 binary characters (i.e. k=1101011). Each binary character is 1 bit or b. There are 8 bits in a Byte or B so 8b=1B.
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So varchar (50) could hold 0 to 50 characters, and would take 52 bytes to store. One byte = 1 character.
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Each binary character is 1 bit or b. There are 8 bits in a Byte or B so 8b=1B.